ʱ¼ä:2017-08-01 02:02:22
1¡¢Ñ¡ÔñÌâ ÏÂÁÐÀë×Ó·½³ÌʽÕýÈ·µÄÊÇ£¨¡¡¡¡£©
A£®Cu2OÈÜÓÚÏõË᣺Cu2O+2H+¨T2Cu++H2O
B£®Ïò¹èËáÄÆÈÜÒºÖÐͨÈ˹ýÁ¿CO2£ºSiO32-+CO2+H2O¨TH2SiO3¡ý+CO32-
C£®ÁòËáÇâï§ÈÜÒºÓëÉÙÁ¿ÇâÑõ»¯ÄÆÈÜÒº·´Ó¦£ºH++OH-¨TH2O
D£®Ì¼ËáÇâ±µÈÜÒº¼ÓÈë¹ýÁ¿µÄ³ÎÇåʯ»ÒË®£ºHCO3-+OH++Ca2+¨TCaCO3¡ý+H2O
²Î¿¼´ð°¸£ºA¡¢Cu2OÈÜÓÚÏõËá±»Ñõ»¯£¬·´Ó¦µÄÀë×Ó·½³ÌʽΪ£º3Cu2O+2NO3-+14H+¨T6Cu2++7H2O+2NO¡ü£¬¹ÊA´íÎó£»
B¡¢Ïò¹èËáÄÆÈÜÒºÖÐͨÈ˹ýÁ¿CO2·´Ó¦µÄÀë×Ó·½³Ìʽ£ºSiO32-+2CO2+2H2O¨TH2SiO3¡ý+2HCO3-£¬¹ÊB´íÎó£»
C¡¢ÁòËáÇâï§ÈÜÒºÓëÉÙÁ¿ÇâÑõ»¯ÄÆÈÜÒº·´Ó¦£¬ÊÇÇâÑõ¸ùÀë×ÓºÍÇâÀë×ӵķ´Ó¦Àë×Ó·½³ÌʽΪ£ºH++OH-¨TH2O£¬¹ÊCÕýÈ·£»
D¡¢Ì¼ËáÇâ±µÈÜÒº¼ÓÈë¹ýÁ¿µÄ³ÎÇåʯ»ÒË®£¬Ì¼ËáÇⱵȫ²¿·´Ó¦£¬£º2HCO3-+2OH++Ba2++Ca2+¨TCaCO3¡ý+2H2O+BaCO3¡ý£¬¹ÊD´íÎó£»
¹ÊÑ¡C£®
±¾Ìâ½âÎö£º
±¾ÌâÄѶȣº¼òµ¥
2¡¢Ñ¡ÔñÌâ ÏÂÁÐÀë×Ó·½³ÌʽÊéдÕýÈ·µÄÊÇ
[? ]
A£®ÂÁ·ÛͶÈëµ½NaOHÈÜÒºÖУº2Al+2OH£¨T¨T 2AlO2£+H2¡ü
B£®AlCl3ÈÜÒºÖмÓÈë×ãÁ¿µÄ°±Ë®£ºAl3++ 3OH£¨T¨T Al(OH)3¡ý
C£®ÈýÂÈ»¯ÌúÈÜÒºÖмÓÈëÌú·Û£ºFe3+ + Fe == 2Fe2+
D£®¶þÑõ»¯Ì¼Í¨Èë¡°Ë®²£Á§¡±ÖУºCO2 + SiO32¨D + 2H2O == CO32¨D+ H4SiO4¡ý
²Î¿¼´ð°¸£ºD
±¾Ìâ½âÎö£º
±¾ÌâÄѶȣºÒ»°ã
3¡¢Ñ¡ÔñÌâ ÏÂÁз´Ó¦ÖУ¬Àë×Ó·½³ÌʽÊéдÕýÈ·µÄÊÇ
A£®ÇâÑõ»¯±µÈÜÒºÓëÑÎËá·´Ó¦£º OH-+H+=H2O
B£®FeºÍÑÎËá·´Ó¦£º2Fe£«6H+£½2Fe3+£«3H2¡ü
C£®Ì¼ËáÇâÄÆÈÜÒºÖмÓÈëÑÎË᣺CO32- + 2H+ =CO2¡ü + H2O
D£®ÄÆ·ÅÓÚË®ÖУºNa£«H2O = Na+£«OH¡ª£«H2¡ü
²Î¿¼´ð°¸£ºA
±¾Ìâ½âÎö£ºA£®ÕýÈ·£»
B£®²»ÕýÈ·£¬FeºÍÑÎËá·´Ó¦£º Fe£«2H+£½Fe2+ £«H2¡ü
C£®²»ÕýÈ·£¬Ì¼ËáÇâÄÆÈÜÒºÖмÓÈëÑÎË᣺HCO3- + H+ =CO2¡ü + H2O
D£®²»ÕýÈ·£¬ÄÆ·ÅÓÚË®ÖУº2Na£«2H2O = 2Na+£«2OH¡ª£«H2¡ü
Ñ¡A¡£
±¾ÌâÄѶȣºÒ»°ã
4¡¢Ñ¡ÔñÌâ ÏÂÁÐÀë×Ó·½³ÌʽÊéдÕýÈ·µÄÊÇ?£¨?£©
A£®ËáÐÔÌõ¼þÏÂKIO3ÈÜÒºÓëKIÈÜÒº·¢Éú·´Ó¦Éú³ÉI2£ºIO3££«5I££«3H2O£½3I2£«6OH£
B£®NaHCO3ÈÜÒºÖмÓÈë¹ýÁ¿µÄBa(OH)2ÈÜÒº£º2HCO3££«Ba2£«£«2OH££½BaCO3¡ý£«2H2O£«CO32£
C£®Cl2ºÍË®·´Ó¦£ºCl2 + H2O ="2" H++Cl- + ClO-
D£®NH4HSO3ÈÜÒºÓë×ãÁ¿µÄNaOHÈÜÒº»ìºÏ¼ÓÈÈ£ºNH4£«£«HSO3££«2OH£NH3¡ü£«SO32££«2H2O
²Î¿¼´ð°¸£ºD
±¾Ìâ½âÎö£ºÂÔ
±¾ÌâÄѶȣºÒ»°ã
5¡¢Ñ¡ÔñÌâ ÏÂÁз´Ó¦µÄÀë×Ó·½³ÌʽÖÐд²»ÕýÈ·µÄÊÇ£¨?£©
A£®Ê¯»ÒʯÈÜÓÚÑÎË᣺CaCO3+2H+¨T¨T Ca2++H2O+ CO2¡ü
B£®ÂÈË®µÎ¼Óµ½ÂÈ»¯ÑÇÌúÈÜÒºÖУºFe2++Cl2 ¨T¨T Fe3++2Cl-
C£®ÌúºÍÁòËáÍÈÜÒº·´Ó¦£ºFe+Cu2+¨T¨T Fe2++Cu
D£®Ï¡ÁòËáºÍÇâÑõ»¯ÄÆÈÜÒº»ìºÏ£ºH++OH-¨T¨T H2O
²Î¿¼´ð°¸£ºB
±¾Ìâ½âÎö£ºBÖеçºÉ²»Êغã
±¾ÌâÄѶȣº¼òµ¥