ʱ¼ä:2017-02-02 07:02:32
1¡¢ÊµÑéÌ⠼ס¢ÒÒ¡¢±û¡¢¶¡Êdz£¼ûµÄµ¥ÖÊ£¬ÆäÖмס¢ÒÒ¡¢±ûÊÇĦ¶ûÖÊÁ¿ÒÀ´ÎÔö¼ÓµÄÆøÌå¡£AºÍBÒÔÎïÖʵÄÁ¿2©U1ͨÈëË®ÖУ¬µÃµ½CÈÜÒº¡£Çë¸ù¾ÝÏÂͼµÄת»¯¹ØÏµ»Ø´ð£º
£¨1£©Ó÷½³Ìʽ½âÊÍAʹʪÈóµÄºìɫʯÈïÊÔÖ½±äÀ¶µÄÔÒò___________________
£¨2£©Ð´³öÈÜÒºCÖмÓÂÈË®µÄÀë×Ó·½³Ìʽ___________________
(3)ÈôAºÍB°´1:1ͨÈëË®Öз´Ó¦£¬Ð´³ö·´Ó¦·½³Ìʽ____________________________¡£
²Î¿¼´ð°¸£º(1) NH3+H2O±¾Ìâ½âÎö£ºÂÔ
±¾ÌâÄѶȣºÒ»°ã
2¡¢Ñ¡ÔñÌâ ÏÂÁйØÓÚÁ×µÄÐðÊöÕýÈ·µÄÊÇ
A£®ºìÁ×ûÓж¾ÐÔ¶ø°×Á×Óо綾
B£®°×Á×ÔÚ¿ÕÆøÖмÓÈȵ½260 ¡æ×ªÎªºìÁ×
C£®°×Á׿ÉÓÃÓÚÖÆ°²È«»ð²ñ
D£®°×Áײ»Äܱ£´æÔÚË®ÖÐ
²Î¿¼´ð°¸£ºA
±¾Ìâ½âÎö£ºÂÔ
±¾ÌâÄѶȣº¼òµ¥
3¡¢Ñ¡ÔñÌâ a mol°±ÍêÈ«Ñõ»¯³ÉHNO3£¬²¢ÇÒÈ«²¿ÈÜÓÚ·´Ó¦Éú³ÉµÄË®ÖУ¬µÃHNO3µÄÖÊÁ¿·ÖÊýԼΪ
A£®78%
B£®42%
C£®50%
D£®63%
²Î¿¼´ð°¸£ºA
±¾Ìâ½âÎö£ºNH3+2O2===HNO3+H2O?
HNO3%=
¡Á100%=78%
±¾ÌâÄѶȣº¼òµ¥
4¡¢¼ÆËãÌâ 3.84 gͺÍÒ»¶¨Á¿Å¨ÏõËá·´Ó¦£¬µ±Í·´Ó¦Íê±Ïʱ£¬¹²ÊÕ¼¯µ½ÆøÌåµÄÌå»ýΪ2.24 L(±ê×¼×´¿ö)¡£ÊÔÇó£º
(1)·´Ó¦ÖÐÏûºÄÏõËáµÄ×ÜÎïÖʵÄÁ¿¡£
(2)°ÑÊÕ¼¯µ½ÆøÌåµÄ¼¯ÆøÆ¿µ¹Á¢ÓÚÊ¢ÓÐË®µÄË®²ÛÖУ¬Í¨Èë¶àÉÙºÁÉý±ê×¼×´¿öϵÄÑõÆø£¬¿ÉÒÔʹ¼¯ÆøÆ¿³äÂúÈÜÒº?
²Î¿¼´ð°¸£º£¨1£©0.22 mol
£¨2£©672 mL
±¾Ìâ½âÎö£º(1)£î£¨£È£Î£Ï£³£©£½
£°£®£±£²£í£ï£ì£«£°£®£±£í£ï£ì£½£°£®£²£²£í£ï£ì¡£
(2)Óɵç×ÓÊØºãµÃ
Íʧµç×ÓÊý£½±»»¹ÔÏõËáµÃµç×ÓÊý£½»¹Ô²úÎï£Î£Ï¡¢£Î£Ï£²ÏûºÄ£Ï£²µÃµ½µÄµç×ÓÊý£¬¼´
Cuʧµç×ÓÊý=£Ï£²µÃµç×ÓÊý£¬±¾ÌâÄѶȣº¼òµ¥
5¡¢Ñ¡ÔñÌâ ¹ØÓÚÏõËáµÄ˵·¨ÕýÈ·µÄÊÇ
A£®Cu¿ÉÒÔÈܽâÔÚÏ¡ÏõËáÖв¢Éú³ÉH2
B£®Å¨HNO3²»ÄÜÓë·Ç½ðÊôµ¥ÖÊ·´Ó¦
C£®ÏõËáÓë½ðÊô·´Ó¦Ê±£¬Ö÷ÒªÊÇ£«5¼ÛµÄµªÔªËصõç×Ó
D£®³£ÎÂÏ£¬ÏòŨHNO3ÖÐͶÈëFeƬ£¬»á²úÉú´óÁ¿µÄºì×ØÉ«ÆøÌå
²Î¿¼´ð°¸£ºC
±¾Ìâ½âÎö£ºÂÔ
±¾ÌâÄѶȣº¼òµ¥