O
-2
+7H++H2O=3Al(OH)3¡ý+Al3+
C£®K37ClO3ÓëŨÑÎËᣨHCl£©ÔÚ¼ÓÈÈʱÉú³ÉÂÈÆø£ºK37ClO3+6HCl=K37Cl+3Cl2¡ü+3H2O
D£®½«25mL?0.1mol?L-1ÑÎËỺ»ºµÎÈë25mL?0.1mol?L-1Na2CO3ÈÜÒºÖУ¬²¢²»¶Ï½Á°è£º2H++CO32-=CO2¡ü+H2O
²Î¿¼´ð°¸£ºA£®ÈýÂÈ»¯ÂÁÈÜÒºÖмÓÈë¹ýÁ¿°±Ë®µÄÀë×Ó·´Ó¦ÎªAl3++3NH3
±¾Ìâ½âÎö£º
±¾ÌâÄѶȣºÒ»°ã
3¡¢Ñ¡ÔñÌâ ÏÂÁÐÀë×Ó·½³ÌʽÕýÈ·µÄÊÇ£¨¡¡¡¡£©
A£®³ÎÇåµÄʯ»ÒË®ÓëÏ¡ÑÎËá·´Ó¦Ca£¨OH£©2+2H+=Ca2++2H2O
B£®ÁòËáÍÈÜÒºÓëÇâÑõ»¯±µÈÜÒº·´Ó¦£ºBa2++SO42-=BaSO4¡ý
C£®Ñõ»¯ÍÈÜÓÚÁòË᣺O2-+2H+=H2O
D£®Ì¼Ëá¸ÆÈÜÓÚ´×ËáÖÐCaCO3+2CH3COOH=Ca2++2CH3COO-+H2O+CO2¡ü
²Î¿¼´ð°¸£ºA£®³ÎÇåµÄʯ»ÒË®ÓëÏ¡ÑÎËá·´Ó¦µÄÀë×Ó·´Ó¦ÎªOH-+H+=H2O
±¾Ìâ½âÎö£º
±¾ÌâÄѶȣº¼òµ¥
4¡¢Ñ¡ÔñÌâ ÏÂÁÐÀë×Ó·½³ÌʽÊéдÕýÈ·µÄÊÇ?? (¡¡¡¡)¡£
A£®³ÎÇåʯ»ÒË®ÓëÉÙÁ¿Ð¡ËÕ´òÈÜÒº»ìºÏ£ºCa2£«£«2OH££«2HCO3¡ª=CaCO3¡ý£«CO32¡ª£«2H2O
B£®´ÅÐÔÑõ»¯ÌúÖÃÓÚÇâµâËáÈÜÒºÖУºFe3O4£«8HI=2Fe3£«£«Fe2£«£«4H2O£«8I£
C£®NaHSO4ÈÜÒºÖеμӹýÁ¿Ba(OH)2ÈÜÒº£ºH£«£«SO42¡ª£«Ba2£«£«OH£=BaSO4¡ý£«H2O
D£®´×ËáÓ백ˮ»ìºÏ£ºCH3COOH£«NH3¡¤H2O=CH3COONH4£«H2O
²Î¿¼´ð°¸£ºC
±¾Ìâ½âÎö£º³ÎÇåʯ»ÒË®¹ýÁ¿£¬ÕýÈ·µÄÀë×Ó·½³ÌʽΪCa2£«£«OH££«HCO3¡ª=CaCO3¡ý£«H2O£¬AÏî´íÎó£»HIÊÇÇ¿ËᣬӦд³ÉÀë×ÓÐÎʽ£¬Í¬Ê±Fe3£«ÄÜÑõ»¯I££¬BÏî´íÎó£»CH3COONH4ÊÇÇ¿µç½âÖÊ£¬Ó¦¸Ãд³ÉÀë×ÓÐÎʽ£¬DÏî´íÎó¡£
±¾ÌâÄѶȣºÒ»°ã
5¡¢Ñ¡ÔñÌâ ÏÂÁз½³ÌʽÕýÈ·µÄÊÇ
[???? ]
A£®ÁòËáÓëÇâÑõ»¯±µÈÜÒº·´Ó¦£º Ba2+ +OH-+H++SO42- = BaSO4¡ý+H2O
B£®ÁòËáÍÓë³ÎÇåʯ»ÒË®·´Ó¦£º Cu2+ +SO42- +C2+ +2OH-=Cu(OH)2¡ý+CaSO4¡ý
C£®Ì¼Ëáï§ÓëÇâÑõ»¯±µÈÜÒº·´Ó¦£º Ba2+ +CO32- =BaCO3¡ý
D£®ÁòËáï§ÓëÇâÑõ»¯±µÈÜÒº¹²ÈÈ£º 2NH4+ +SO42- +Ba2+ +2OH- =BaCO3¡ý+2NH3¡ü+2H2O
²Î¿¼´ð°¸£ºBD
±¾Ìâ½âÎö£º
±¾ÌâÄѶȣºÒ»°ã