1¡¢Ñ¡ÔñÌâ  ÏÂÁеÄÀë×Ó·½³ÌʽÕýÈ·µÄÊÇ£¨¡¡¡¡£©
A£®ÓôóÀíʯ¸úÏ¡ÑÎËáÖƶþÑõ»¯Ì¼£ºCO32-+2H+¨TH2O+CO2¡ü
B£®CuË¿ÉìÈëµ½AgNO3ÈÜÒºÖУºCu+2Ag+¨TCu2++2Ag
C£®H2SO4ÈÜÒºÖеÎÈëBa£¨OH£©2ÈÜÒº£ºBa2++OH-+H++SO42-¨TBaSO4¡ý+H2O
D£®ÌúÐâÓëÏ¡ÑÎËá·´Ó¦£ºFe2O3+6H+¨T2Fe3++3H2O¡ü

2¡¢Ñ¡ÔñÌâ  ÏÂÁз´Ó¦µÄÀë×Ó·½³Ìʽ²»ÕýÈ·µÄÊÇ
A£®ÌúÓëÏ¡ÑÎËá·´Ó¦£º2Fe+6H+=2Fe3++3H2¡ü
B£®ÇâÑõ»¯ÄÆÈÜÒºÓëÑÎËá·´Ó¦£ºOH¡ª+H+=H2O
C£®Ð¿ÓëÁòËáÍ­ÈÜÒº·´Ó¦£ºZn+Cu2+=Zn2++Cu
D£®ÂÈ»¯±µÈÜÒºÓëÏ¡ÁòËá·´Ó¦£ºBa2++SO42¡ª=BaSO4¡ý

3¡¢Ñ¡ÔñÌâ  ÄÜÕýÈ·±íʾÏÂÁл¯Ñ§·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ

[???? ]

A£®½ðÊôÂÁÈÜÓÚÑÎËáÖУºAl+2H+£½Al3++H2¡ü
B£®Ì¼ËáþÈÜÓÚÏõËáÖУº2H++CO32-£½CO2¡ü+H2O
C£®ÁòËáÇâÄÆÈÜÒºÖмÓÈë̼ËáÇâÄÆÈÜÒº£ºH++HCO3-£½CO2¡ü+H2O
D£®ÔÚ³ÎÇåʯ»ÒË®ÖÐͨÈë¹ýÁ¿µÄCO2£ºCa2++2OH-+CO2£½CaCO3¡ý+H2O

4¡¢Ìî¿ÕÌâ  °´ÒªÇóд³ö¶ÔÓ¦µÄÀë×Ó·½³Ìʽ
£¨1£©Ð´³öÿ²½ÏÖÏó¶ÔÓ¦µÄÀë×Ó·½³Ìʽ£ºÏòFeCl3ÈÜÒºÖÐÖðµÎ¼ÓÈëNa2SÈÜÒº£¬ÏȲúÉúµ­»ÆÉ«³Áµí£¬ºóÓÖ²úÉúºÚÉ«³Áµí______________¡¢_______________
£¨2£©ÏòÃ÷·¯ÈÜÒºÖеμÓBa(OH)2ÈÜÒºÖÁ³ÁµíÎïÖʵÄÁ¿×î´ó£º_________________?????????????
£¨3£©Ïò̼ËáÇâ±µÈÜÒºÖеμӹýÁ¿µÄNaOHÈÜÒº£º___________________?????????????
£¨4£©Ïòº¬1molFeI2µÄÈÜÒºÖÐͨÈë1.2molµÄCl2£º___________________

5¡¢Ñ¡ÔñÌâ  ÏÂÁÐÀë×Ó·½³ÌʽÕýÈ·µÄÊÇ????????????????????????????????????????????????????????????????????????????????????????????£¨???£©

A£®ÒÒËáÓë̼ËáÄÆÈÜÒº·´Ó¦£º2H++CO32-CO2¡ü+H2O

B£®¼×ËáÈÜÒºÓëµÎÈËÉÙÁ¿µÄÐÂÖÆÇâÑõ»¯Í­ºó¹²ÈÈ£º

¡÷

HCOOH+2Cu£¨OH£©Cu2O+CO2¡ü+3H2O

¡÷

C£®±½·ÓÄÆÈÜÒºÖÐͨÈËÉÙÁ¿¶þÑõ»¯Ì¼£º2C6H5O-+CO2?+H2O2C6H5OH+CO32-
D£®¼×È©ÈÜÒºÓë×ãÁ¿µÄÒø°±ÈÜÒº¹²ÈÈ£º

HCHO+4[Ag£¨NH3£©2]++4OHCO32-+2NH4++4Ag¡ý+6NH3+2H2O

Ê×Ò³ ÉÏÒ³ 1 2 3 ÏÂÒ³ βҳ 2/10/10

¡ï ¸ß¿¼Ê¡¼¶µ¼º½ ¡ï

È«¹ú A°²»Õ B±±¾© CÖØÇì F¸£½¨ G¹ã¶« ¹ãÎ÷ ¸ÊËà ¹óÖÝ HºÓÄÏ ºÓ±± ºþÄÏ ºþ±± ºÚÁú½­ º£ÄÏ J½­ËÕ ½­Î÷ ¼ªÁÖ LÁÉÄþ NÄÚÃɹŠÄþÏÄ QÇຣ Sɽ¶« ɽÎ÷ ÉÂÎ÷ ËÄ´¨ ÉϺ£ TÌì½ò Xн® Î÷²Ø YÔÆÄÏ ZÕã½­

 ¡ï ¸ß¿¼ÐÅÏ¢»ã×Ü ¡ï   ¡ï ¸ß¿¼ÀúÄêÕæÌâ ¡ï   ¡ï ¸ß¿¼ÀúÄêÕæÌâ ¡ï   ¡ï ¸ß¿¼Ìâ¿â ¡ï   ¡ï ¸ß¿¼Ìâ¿â ¡ï