ʱ¼ä:2019-05-30 04:16:15
1¡¢¼ò´ðÌâ ÒÑÖªÏÂÁÐÈÈ»¯Ñ§·½³Ìʽ£º
£¨1£©C£¨s£¬Ê¯Ä«£©+O2£¨g£©¨TCO2£¨g£©¡÷H=-393.5kJ?mol-1
£¨2£©2H2£¨g£©+O2£¨g£©¨T2H2O£¨l£©¡÷H=-571.6kJ?mol-1
£¨3£©2C2H2£¨g£©+5O2£¨g£©¨T4CO2£¨g£©+2H2O£¨l£©¡÷H=-2599kJ?mol-1
Çëд³öC£¨s£¬Ê¯Ä«£©ºÍH2£¨g£©Éú³É1mol C2H2£¨g£©µÄÈÈ»¯Ñ§·½³Ìʽ______£®
2¡¢Ñ¡ÔñÌâ ÒÑÖª101KPaʱÐÁÍéµÄ±ê׼ȼÉÕÈÈΪ¡ª5518kJ¡¤mol-1£¬º¬20gNaOHµÄÏ¡ÈÜÒºÓëÏ¡ÑÎËá³ä·Ö·´Ó¦·Å³öÈÈÁ¿28.7kJ£¬ÔòÏÂÁÐÈÈ»¯Ñ§·½³ÌʽÊéдÕýÈ·µÄÊÇ
¢ÙC8H18£¨l£©+ 25/2O2£¨g£©£½ 8CO2£¨g£©+ 9H2O£¨g£©£» ¡÷H £½ +5518 kJ¡¤mol-1
¢ÚC8H18£¨l£©+ 25/2O2£¨g£©£½ 8CO2£¨g£©+ 9H2O£¨l£©£» ¡÷H £½ £5518 kJ¡¤mol-1
¢ÛH+£¨aq£©+ OH-£¨aq£©£½ H2O£¨l£©£» ¡÷H £½ £57£®4 kJ¡¤mol-1
¢ÜHCl (aq) + NaOH(aq) £½NaCl(aq) + H2O(l)£» ¡÷H £½ ¡ª28.7 kJ¡¤mol-1
A£®¢Ù¢Û
B£®¢Ú¢Û
C£®¢Ú¢Ü
D£®¢Ú
3¡¢Ìî¿ÕÌâ (15·Ö£©¼×´¼¿É×÷ΪȼÁÏµç³ØµÄÔÁÏ¡£¹¤ÒµÉÏÀûÓÃCO2ºÍH2ÔÚÒ»¶¨Ìõ¼þÏ·´Ó¦ºÏ³É¼×´¼¡£
£¨1£©ÒÑÖªÔÚ³£Î³£Ñ¹Ï£º
¢Ù2CH3OH(l) £« 3O2(g) £½ 2CO2(g) £« 4H2O(g) ¦¤H£½£1275.6 kJ£¯mol
¢Ú2CO (g)+ O2(g) £½ 2CO2(g) ¦¤H£½£566.0 kJ£¯mol
¢ÛH2O(g) £½ H2O(l) ¦¤H£½£44.0 kJ£¯mol
д³ö¼×´¼²»ÍêȫȼÉÕÉú³ÉÒ»Ñõ»¯Ì¼ºÍҺ̬ˮµÄÈÈ»¯Ñ§·½³Ìʽ£º ¡£
£¨2£©¼×´¼ÍÑÇâ¿ÉÖÆÈ¡¼×È©CH3OH(g)
HCHO(g)+H2(g)£¬¼×´¼µÄƽºâת»¯ÂÊËæÎ¶ȱ仯ÇúÏßÈçÏÂͼËùʾ¡£»Ø´ðÏÂÁÐÎÊÌ⣺
¢Ù600Kʱ£¬Yµã¼×´¼µÄ¦Ô(Äæ) (Õý)£¨Ìî¡°>¡±»ò¡°<¡±£©
¢Ú´ÓYµãµ½Xµã¿É²ÉÈ¡µÄ´ëÊ©ÊÇ______________________________________¡£
¢ÛÓÐͬѧ¼ÆËãµÃµ½ÔÚt1Kʱ£¬¸Ã·´Ó¦µÄƽºâ³£ÊýΪ8.1mol¡¤L£1¡£ÄãÈÏΪÕýÈ·Âð£¿Çë˵Ã÷ÀíÓÉ ¡£
£¨3£©ÄÉÃ×¼¶Cu2OÓÉÓÚ¾ßÓÐÓÅÁ¼µÄ´ß»¯ÐÔÄܶøÊܵ½¹Ø×¢¡£ÔÚÏàͬµÄÃܱÕÈÝÆ÷ÖУ¬Ê¹Óò»Í¬·½·¨ÖƵõÄCu2O£¨¢ñ£©ºÍ£¨¢ò£©·Ö±ð½øÐд߻¯CH3OHµÄÍÑÇâʵÑ飺CH3OH(g)
HCHO(g)+H2(g)
CH3OHµÄŨ¶È£¨mol¡¤L£1£©ËæÊ±¼ät (min)±ä»¯ÈçÏÂ±í£º
| ÐòºÅ | ÎÂ¶È | 0 | 10 | 20 | 30 | 40 | 50 |
| ¢Ù | T1 | 0.050 | 0.0492 | 0.0486 | 0.0482 | 0.0480 | 0.0480 |
| ¢Ú | T1 | 0.050 | 0.0488 | 0.0484 | 0.0480 | 0.0480 | 0.0480 |
| ¢Û | T2 | 0.10 | 0.094 | 0.090 | 0.090 | 0.090 | 0.090 |
4¡¢Ñ¡ÔñÌâ ÓÃCH4´ß»¯»¹ÔNOx¿ÉÒÔÏû³ýµªÑõ»¯ÎïµÄÎÛȾ¡£ÒÑÖª
ÏÂÁÐ˵·¨²»ÕýÈ·µÄÊÇ
[? ]
A£®µÈÎïÖʵÄÁ¿µÄCH4²Î¼Ó·´Ó¦£¬·´Ó¦¢Ù¢Ú×ªÒÆµÄµç×ÓÊýÏàͬ
B£®CH4(g)+4NO2(g)=4NO(g)+CO2(g)+2H2O(l);¨SH=-618KJ/mol
C£®0£®2 mol CH4»¹ÔNO2ÖÁN2£¬ÇÒÉú³ÉH2O(g)·Å³öµÄÈÈÁ¿Îª173£®4kJ
D£®ÈôÓÃ4£®48 L(±ê×¼×´¿ö)CH4»¹ÔNO2ÖÁN2£¬Õû¸ö¹ý³ÌÖÐ×ªÒÆµç×Ó1£®60mol
5¡¢Ìî¿ÕÌâ £¨6·Ö£©ºìÁ×£¨P£©ºÍ°×Á×£¨P4£©¾ùΪÁ×µÄÍ¬ËØÒìÐÎÌå¡£ÒÑÖª£º
P4 ( °×s )£« 5O2 ( g )£½ P4O10( s ) ¡÷H =" -2983.2" kJ/mol
P(ºì s )£« 5/4O2 ( g )£½ 1/4P4O10( s ) ¡÷H =" -738.5" kJ/mol
д³ö°×Á×ת»¯ÎªºìÁ×µÄÈÈ»¯Ñ§·½³Ìʽ ,ÓÉ´Ë¿ÉÖª£¬ºìÁױȰ×Á× ¡££¨Ìî¡°Îȶ¨¡±»ò¡°²»Îȶ¨¡±£©