ʱ¼ä:2017-08-22 16:59:07
1¡¢Ñ¡ÔñÌâ NH4CuSO3ΪÄÑÈÜÓÚË®µÄ°×É«¹ÌÌ壬µ«Óë×ãÁ¿µÄÖÊÁ¿·ÖÊý50%µÄÁòËá»ìºÏ΢ÈÈ£¬Éú³ÉºìÉ«¹ÌÌåÎï¡¢²úÉúÓд̼¤ÐÔÆøÎ¶µÄÆøÌåºÍÀ¶É«ÈÜÒº£®¾Ý´ËÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ£¨¡¡¡¡£©
A£®·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ£º2Cu++2SO32-+4H+¨TCu+Cu2++2SO2¡ü+2H2O
B£®NH4CuSO3ÖÐÁòÔªËØ±»Ñõ»¯
C£®´Ì¼¤ÐÔÆøÎ¶µÄÆøÌåÊǰ±Æø
D£®1molNH4CuSO3ÍêÈ«·´Ó¦×ªÒÆ0.5molµç×Ó
2¡¢Ìî¿ÕÌâ £¨1£©ÇëÖ¸³öÏÂÁÐ×ö·¨ÖзֱðÓ¦ÓÃÁËÄÄЩ·ÖÀë·½·¨£¿£¨¹ýÂË¡¢Õô·¢¡¢ÕôÁó¡¢ÝÍÈ¡¡¢½á¾§£©
a¡¢°¾ÖóÖÐÒ©______?b¡¢·ÖÀë¶¹½¬ºÍ¶¹Ôü______
c¡¢Óú£Ë®É¹ÑÎ______?d¡¢º£Ë®µ»¯______
£¨2£©Ð´³öÀë×Ó·´Ó¦·½³ÌʽH++OH-=H2OËù¶ÔÓ¦µÄÁ½¸ö²»Í¬ÀàÐÍ»¯Ñ§·½³Ìʽ
¢Ù______
¢Ú______
£¨3£©£®ÔÚÏÂÁз´Ó¦ÖУº
A.2F2+2H2O=4HF+O2?B.2Na+2H2O=2NaOH+H2¡ü
C£®CaO+H2O=Ca£¨OH£©2?D.2H2O=2H2¡ü+O2¡ü
ˮֻ×÷Ñõ»¯¼ÁµÄÊÇ______£¬Ë®Ö»×÷»¹Ô¼ÁµÄÊÇ______£¬Ë®¼È×÷Ñõ»¯¼ÁÓÖ×÷»¹Ô¼ÁµÄÊÇ______£¬Ë®¼È²»×÷Ñõ»¯¼ÁÓÖ²»×÷»¹Ô¼ÁµÄÊÇ______£®ÇëÓÃÏßÇűíʾB·´Ó¦µÄµç×Ó×ªÒÆ·½ÏòºÍÊýÄ¿£®
2Na+2H2O=2NaOH+H2¡ü
3¡¢Ìî¿ÕÌâ ÒÑÖªÏÂÁз´Ó¦£º14HCl+K2Cr2O7=2KCl+2CrCl3+3Cl2¡ü+7H2O£¬¸Ã·´Ó¦µÄÑõ»¯¼ÁÊÇ______£¬»¹Ô²úÎïÊÇ______£¬¼È²»ÊÇÑõ»¯²úÎïÓÖ²»ÊÇ»¹Ô²úÎïµÄÊÇ______£¬µç×Ó×ªÒÆ×ÜÊýÊÇ______£®
4¡¢Ñ¡ÔñÌâ ÏÂÁÐÎïÖÊÖв»ÄÜͨ¹ýÖû»·´Ó¦Éú³ÉµÄÊÇ£¨¡¡¡¡£©
A£®F2
B£®CO
C£®Fe3O4
D£®S
5¡¢Ñ¡ÔñÌâ ÏÂÁйØÓÚÑõ»¯»¹Ô·´Ó¦Ëµ·¨ÕýÈ·µÄÊÇ£¨¡¡¡¡£©
A£®¿Ï¶¨ÓÐÒ»ÖÖÔªËØ±»Ñõ»¯£¬ÁíÒ»ÖÖÔªËØ±»»¹Ô
B£®Ä³ÔªËØ´Ó»¯ºÏ̬±ä³ÉÓÎÀë̬£¬¸ÃÔªËØÒ»¶¨±»»¹Ô
C£®ÔÚ·´Ó¦Öв»Ò»¶¨ËùÓÐÔªËØµÄ»¯ºÏ¼Û¶¼·¢Éú±ä»¯
D£®ÔÚÑõ»¯»¹Ô·´Ó¦ÖзǽðÊôµ¥ÖÊÒ»¶¨ÊÇÑõ»¯¼Á